该【高考数学一轮复习 导数问题强调知识梳理2 苏教版 】是由【jia0277li】上传分享，文档一共【7】页，该文档可以免费在线阅读，需要了解更多关于【高考数学一轮复习 导数问题强调知识梳理2 苏教版 】的内容，可以使用淘豆网的站内搜索功能，选择自己适合的文档，以下文字是截取该文章内的部分文字，如需要获得完整电子版，请下载此文档到您的设备，方便您编辑和打印。 : .
1
f(x ) = \n (\+ x ]--^ -(6Z >0)
1!"#$2011%&'()*+, $ ' ' ' 1 + aN )
( I ) / 0 (0,+oo)123456a 789:;
( I I ) /" = 0 x = 0 >7?***@A856a 789:.
CDA E F G H I x ?a
(1 + X)(1 + OV)2
( I ) /(= 0 (0,+oo)1234 0 (0,+oo)LMN O .P Q> 0 ,
x ( x - i ^ ) N00 (0,+<)LMNO5 4 2 4
R_1 - 2a I
( I I ) TU(x) = 'X VW = 0 ?X= 0 / =L Z (”> 0)
(l + x)(l + ar)~ Q
]0 < < 4 ^ ,TU(r)> 0 ? x w (-l,0 )U ( 4 ` ” ) 5TU(x)vO ? X !( O,f g )
b = 0 l = L c > 7 ? ***@A8. ( de
)
(2)a = J ^5/'(%) = ---- - ---- 2 0 x e ( - l,+oo)MNO.
2 (l + x)(l + ar)-
x )******@A8.
(3)a n4 ^5T /Q )>0? T U(=<0 ?
p^/ 0 x = 0 >7?***@A8.
qL5f ( x ) 0 x = 0 >******@A8^5aw A.
r=ND!08stu22*. iv/ " ) = S'"
2 + cosx
( I I ) w x y z/( x ) W a r , 6b789:.
2 cos r +1 2 3
CD(I I ) { g(x) = a x -f( x ) | g\x) = a --------- ---- 7 = a ---------- 1------------ -
(2 + cosx) 2 + cos x (2 + cosx)~
3 f-J I f \
+ a .
12 + cos x 3 3
^5g '( x ) 2 0 .P g(0) = 0 ,} ~2 0 ^5g (x )2 g (0 ) = 0 ,
0va< "!^5
3
aW O ^5 p5a 789: L + oo
2 2 |_3
De> > ; : .
68l.du'fF
¡¢> .
2D¤¥¦
§¨©ª«¬®A«¯8MNO«C§°ez±²¤¥³´
µ¶°e5·¸¹°eº» 5
3 Q
2D!¼½¾2011ÁÂ)10Ã 12(*17 . +,/(x) = W -(x > 0 Æ w l ) .
In x
( 1 ) 6f(x)***@8;
( 2 ) / § ¨ > x
ÌÍMNO56ÌQ789:.
CD( 1 ) b Î ==Ïjkl2(0,l)U(l,+8)5 / " ) = Ó u 5
In x ln- x
{ r(x)= 0 , C?x = ÕÖTÖ?/(x)3×Ø2(OJ), (l,e),3×Ø
2(e,+8);} @ A 8 2 = e , m@®8.
( 2 ) x W O ^5x
QÝ0 , §¨MNO; x > 0 ^50 Þ ß 7 à á 5
?â >lnx,
a
ãO v x V l ^5I n x W O , Q> 0 , §¨MNO; w avO, l nx<0, 6tlnx>0,
§¨§éa < L 5 T(1)?5p^Gâê ( 3 , 0 ) , §¨ MNO.
\nx Inx
2Q”> 1 ^5l n x > 0 , |a > 0 , §¨§éa ìL 5T(1)?5p^L ¯ A82e ,
Inx Inx
?
qLDa 789:0va< e .
!íª*e)îïðñ3«******@8««ò ¶«óô
õö« §¨«MNO°e> ÷ø.
3D§éò ¬®A
§¨MNO«©ª §¨§°eùú
ò §é.
3D109½ü.ý±*14.ÿ/(x) = x3 2 e f + I n x , g(x) = Z ,
x
g(x)
!"#$%&'( ) .
( 2 1]
-co, e + -
I 0/
0:2345g(x) = / 6 # 7 89.
X
23;<=>?***@g(x) = A B = ()CDE>?***@FGH .
X : .
IJKLMNOPQRS2011UVW12XYZ[ /(x) = 2xln x,^(x) = -x2 + ar - 3
o
(1)`f(x)#a"%b
(2)xc(O,+8),f /(x)Vg(x)Lh `!a #$%&'b
(3)ijklxw(0,+oo),nCf(x)>2p - 2)Lhq
ex e
DO(1) /(%)#stu@(0,y), r(x) = 2(lnx+l), .........1 w
x / " ) = 0 , z{={
e
|x w ( o , 3 } r ( x ) < o b|5([,” )} r(x)>o, .........3 w
e e
/(x) Xc(O/)78b xwd,+oq)78
e e
1 7
|x = }/(x)$a"%@;q ..........5 w
e e
(2)xw(0,+ao), f /(x)Wg(x)Lh Z r l n x W r ? + - 3 xe(0,+oo)IL
3
h <=a N 21nx+ x + c(0,+8)ILhb
x
<=aN(21nx+x+3)n .........8 w
x
3
J(x) = 21nx+x+ , X G (0,+oo)
X
= + 1 - a
X X X X
| (0,1)} '()<0 b|xe(L+oo)} hXx) >0,
|x = l}($a"%***@4 , q2 4 q ..........11w
x 2 1 x
(3) / =2(;)xw(0,+a)), M/(x) = 2( )
e e e
|xe(0,l)} /(x)>0O|xw(l,+8)} /( <0,
2
|x = l} (x)$a%@-q ..........14w
e
1 2
(1)¡|{=}/( $a"%@
e e
kl X(0,+8), nC f (X)> 2(;"2)Lhq ..........16 w : .
k£¤¥¦ ${= C ln( +§ )> ¨ 1.
IJKLOP©ª09¬8[¡/(x) = lnx-x + l, xe(0, + oo).k£¤x c (0,+ 8 ) ,
`4 i T O--1- -< -X-+-1- < -1.
x+1 x x
DOxA l = f , x = /_, Vx>0, /.r>l,±²<³<=l/ < h w u 1
x r-1 t
(1)¡ /(f) = ln/T + l(L+oo)78 / q) < 1/^1) = 0 , ln/vz-1
x ¸ ) = lnf l + b, ," ) = U = 7 , |/e(L+oo)} ()>0
J( )=111-1 + b(1,»)78 (/)>¼)=0
½¾ k£¤xw(0, + 8 ) , ¿C/ ¬ Lh.
A + l A X
IJÀÁOP©ÂÃÄ10T1ÅÆÇ[20.¡ /(x) = a r - lnx,8({ ) = ; È asR.
x
É|q= 1 } ÊË/(X)#789ÌÍ%b
(2)|q=1 } `iO8(/) /(Î)< 2 Î+ 3 VX],42 c(° *°)Lhb
(Ò! f xw(0,e]} /(X)#a"%(3, `Óq#%b²,
ÔjÕ .
D O(1) a=l } f(x) = x - In x, f r(x) = Ö- (x > 0), x>l } /'(x) >0,x v O }
x
r ( x ) < 0 ,
f (x) (0, 1)78 (1,40q)78 f (x)CÍ
" % f (1) T
/cÌ / Ì x+lnx , Inx / Ì 1-lnx - / Ì /, Ì c 1
(2)a=-l } g(x) = ------ = 1 + g(x) = 3 ×J(x) = /(x) + 2x + - ,
x x x 2
1 3
(x) = x-lnx + - , C1)¡ h (x)#a"%@qÙ***@g (x) (0, e)
2 2
1 3
78 (e,+Oq)78
g ( X ) a%@
e 2
g(W) < x2 G (° +00)Ú: g( W )- f(x )<2x + - y x x (0, +oo)L
] l lt 2
h
(3)Û×!q f /(x) = ar-lnx ( x w (0,e]) Ca"% 3, f ,(x) = a ~
x
4
Ü | } /(%) (0,c]78 /(x)min =/ ( 6 ) = ß - 1 = 3 , q= (à) : .
á}/(X )âa"%q
ã | 0 < < e } /(%)(0 ,1 )78 d ,e 78
a
高考数学一轮复习 导数问题强调知识梳理2 苏教版 来自淘豆网m.daumloan.com转载请标明出处.
