高考数学一轮复习强化训练题汇总4（含解析）.pdf

该【高考数学一轮复习强化训练题汇总4（含解析） 】是由【jin2202537】上传分享，文档一共【7】页，该文档可以免费在线阅读，需要了解更多关于【高考数学一轮复习强化训练题汇总4（含解析） 】的内容，可以使用淘豆网的站内搜索功能，选择自己适合的文档，以下文字是截取该文章内的部分文字，如需要获得完整电子版，请下载此文档到您的设备，方便您编辑和打印。 : .







P307
  70   100
 8 !  "#!5  " 40.%#!&'()*+"
,-*./0123(
1 .45
678(9:*;<Sn"=  > <+2=2%+1 - 7 A = 4 - a "C $ =  
A . 7 B . 12
C . 14 D . 21
C E %+2 = 2%+1 - %5
6% 8<GH
"E I J4 -< K I +L = 4 = d + < "
7  + 
M N S J = 14.]
2
2 .%GH
6<8+ "OJP12 + 3 ,C
6R ( 9 11* ; S i =

A . 24 B . 48
C . 66 D . 132
1 1
C [%GH
T8+ , U =5V + 3 , /.ai + 8y = -
ai + llo  + 3 ,W ' + 5 d = 6 "J
11

a (9 11 *; S i = 5 &+ &1 = 11
( + 50 = 11x6 = 66.]
I l l 1
3 .
2019
XYZ[\]45 Sn - ~ ^ + - r= ^+ p + ... + 1........ -
\j2 + l W + W 2+yj3 yjn+ l +
_ ` = 1 0 ,C 6 =

A . 11 B . 99
C . 120 D . 121
c [&$ = 5 -1  + a - g + ) +
g - X  1 + N " + l - = -1.
Sm = \jm + 1 - 1 = 10 ,K 777= 120.] : .
4 . 2018bcdefg45h ij(GI
6. 8,_7
7o = 100 ,k l ! + V
(m!n< 
A . 20 B . 25
C . 50 D .op%
A [7+ 74qJr+ s4 + 27<t47<4 = 4(7o=+ ai4>20.]
5 . 2019vwxyz{GI

a:8+ ".
6| ( 9 "* ; "S = 14 ,~ ' +
8,3
"<+ 6 sjGH
"C€<G 
A . 4 B . 9
C . 16 D . 25
C = % + <+ E= 1 4 ,a + 8 + E+ 6 = 67 "/.77= 28 ,‚ < = 4 ,Jƒ4 =
16.]
6 . 45
6/ 8 > 3+ i- <=2 , ai= - 5 , C|†+ |7| + ... + |I| =  
A . 9 B . 15
C . 18 D . 30
C [E‡5
a:8. N 2 <ˆH(GH
"‰ < J5 ,MN|&| + ‹ + ... + |Œ| = |
-5| + | -3| + |-1 | + 1 + 3 + 5 = 5 + 3 + 1 + 1 + 3 + 5 = 18.]
7 . 45
678+ an= -4/7+5 , GI

6 ( ˆ I q  > q=an-an-in>2
^.
 = Ž "C  | + |fe| + 1’| + ... + 1“ =  
A . 1 - 4" B . 4“ - 1
1 -4 " 4" - 1
C ' 3 D , 3
B [E 4 5 K ’ =” =-3 ,q= -4 , .
’ = -3 x-4 " • "
!.I– = 3 x 4 -1, ‚6|— ˜ N 3 <™*,4 <ˆI(GI
.
3 1 -4 
.!.|61| + |6z| + ... + \br\=$ : - -- = 4 -1.]
1 -4
1
8 .š › œ * = 3 /%žŸ ¡ž¢£<2¤¥(“œ¦§¨©£(ª«¬­< : .
“+i , ® + /WN* ,_ ” =32 ,C 7 + &4 + ¯ = ( )
A . 64 B . 42
C . 32 D . 21
1
B [vy= 2/ (x> 0), .y = 4 x. / = y %žŸ ¡ž¢£(”2%)¥(“œ²
³ . ^ 2´J4µx - ¶ "· ¸ "K 4“ ^ 2´J0 ,

“ œ ¦ x ¨©£(ª«¬<¹+i ,
1 1
0+1 = 5¹".67º.™*<32 = 32 , ˆ I q J»GI
” .7+ 84 + % = 32+ 8+ 2 =
42.]
J½¾( 4 !  "#!5  " 20.¿ÀÁ½%+ªœ¢)
9 .45h*GI
6| + L a a 3 a 6 = 256 = 2"C
6Â8( ˆ I < .
 [
.h*GI
6¯8+ "7Ã
'3 4 6 = 256 ,Ä =7 I V a 6 = 256 ,W K E
à Å
= 4 "‰ 7 =2 ".J "•678(ˆIq =  = /2.]
10 . (2018
ÆÇÈÉJf)%
6¶8+ "45(J1 ,% + 1 + ( - 1) =cos(/?+ l)n ,
­ S <
6Ê8( 9 "* ; "C S ( H 5 J .
- 1 006 [ . a i + (- l)na =cos(n+ l)n = ( - l)n + 1 "JË n -2 k , AreN* , 7:+i
n+ n
+ 31k ~ 1 , 015 = + (7 + <)+ ... + (< 014 + 31 015)= 1 + (- 1)x1 007 = - 1 006.]
11 . (2018
ÌYÍÎf)ÏGI
6<8(ˆI<q ,9 º*;<5 , , _ S , 1, S ,,
S“+2jGH
"C q ( n < .
- 2 [ÏGI
6/ 8(ˆI<g , 9 "* ; < S , ~ Ð +1 , 5° , ) + 2jGH
"
C 2S?= S+i + S + 2 I
q = l ,C Sn=n, N Ñ Ò o j Ó "
a\ X - cf ai \ - 0n+i ai 1 - cf^2
 # 1 ,ÔÕJ< 2-- -- ---------=------ :---------- +------ -------- "Ö 2 / = J+1 + 6+
1 - q 1 - q 1- q
2 , ‚ q2 + q - 2 = 0 , ×Ø q - - 2.]
12 . 45
6Â.Ù*Úo<Û(GH
"S <®9" * ; "~ < = < ÝJ("Þ : .
A n+ 8
7 - ß ‡ " ) N !àjÓ"Cá 7(mn<
31 + din-1 I----------
-----------= yj 2 n - 1 3n ,^af,= (2n-
l)an=>an = 2 n - 1, neN*.
A n+8 n+8 2n-l 8 8
 <----â.<w------------------ =>A<2n -- +15. 2 n - ~ + 15 % n>l äzå
an n n n n
æ ,®m!n<9 ,MN/I49 ,Öá ç(mn<9.]
èWÀ(WÀ
é'êëìí îíï³ðñò¤ó)
13 .(10)(2019!ôõõö÷øù])ÏGH
69 ( 9 " *;<S:"45<J- 3 ,
5io = - 40.
Q)3
6% 8(ú*ˆûÄ
(2)_ü
6% 8+sý'2,4,8 ; 2” þ* ,ÿ
f

,

=6 >7k
 Q)/as = & + 4d= - 3 ,
5io= 10(?i + 45(y= - 40 ,
 5 , d- - 2..'.3n= ~ 2/7+ 7.
(2)bn=d2n= -2x2F + 7 = -2F+1 + 7,
 % = - (22 + 23 + ;+ 2"+1) + 7
22 - 2"+1x2
= 4 + 7n- 2"+2.
1
14 . (10!)(2018" # $%)'
( ) *=5 ,   "  S , - S+i
(1]
-Sn= ~ ”+l("WN*) .
.
/012an ..450   S 6 : .
7 8 S + S , S + S , /7XS+ $ :;<
=
m > .
0 (i\
 (1) .N/J+I = S + L & = | 5 "+1."22 ? , a„= " K
1
@  =5 , A B n - 1 ?CD.
E F G HI F
1 --
1 3 7
(2)I(1)J  51 = ;Z , S = 4] ,  = ?o
 5 +S , S KS , XS + $);<

1 3 (3 7] (1 7] 12
W+Z+L + J =23  F
15 .(10!)(2019
O#PQRS S
%   "   TUV; 2 ,XY/7GN\
Z[ 2S=(/7+l)a.
(1)
80126
4 1
(2)8
 \ a "   S 7Z  ^ _-< Tn<l.
an an + 2 2
(1) AS2 s =("+1)V 
b n>2 ? 2 = nan -\,
, 3n 3n-l
c2de 2a=("+l)8- nan - \ f(" Y]an -nan- \ h 4 b i 2 ? j = j ~ ,
n n - 1
3 n (
h4j = 7 = 2 , f an =2n(n>2).
n 1
4
(2)^l an = 2 n ,m bn = -------- - ,
3n do +
4 1 1 1
h4 bn = ~ T - = - = - - 7.
2n 2/7+2 n n + 1 n n + 1 : .
h4 Tn =bi+b2 + ... + bn
1 1 (1 1 G1
I / + ... +
(2 3) “ n+1
1
ASQ > ,
1
h4
1 1
opb" = 1 ? qrst>5. h 4 Tn<l.
16 . (10!)
& , - :w =2 , x =3 , / +2 = 3/+1 - 2%(/?5N").
. y dn=%+1an , ^ _

&Jz;{