解一元一次方程运算题.doc

解一元一次方程计算题一、去括号:(1)7 6 22 6x x? ???(2)4x-3(20-x)=6x-7(9-x)(3)3 7 3 5y y? ???.(4)4 3 5 2x x? ????;(5)xx23273???(6)5476???xx(7)2x+5=5x-7(8)3(x-2)=2-5(x-2)(9)7x+6=8-3x(10)2234191()()()xxx?????(11))2(3)3(41????xx(12)4(x-2)-[5(1-2x)-4(5x-1)]=0(13))1(16)12(32?????xxx(14)??4 3 20 4 0x x? ???(15)2(2 1) 2(1 ) 3( 3)x x x? ????(16)2)31(35???y(17)(5x-10)-3(2x+5)=1(18)312???xx(19)32)]4(212[?????xxx(20)5 2 7 8x x? ??(21)、20)33(27???xx(22)、)3(23)1(73?????xxx(23)3(x+2)-2(x+2)=2x+4(24)2(10-)=-(+2)(25)7 6 16 3x x? ??;(26))5(4)3(2????xx(27).2( 5) 82xx? ???(28)4x-3(20-x)=6x-7(9-x)(29).18x+3x-4x=18-2×3(30)、8(3x-1)-9(5x-11)-2(2x-7)=30(31)????32123????xx(32)(20-x)=6x-7(9-x)二、去分母:6171315213??????yyy4 5 x x? ??? ?1}8]6)432(51[71{91?????x32]3)12(23[34????]2)(32[23????32221?????xxx135467221??????xxx)4211(52661xx?????237x--514x+=1**********??????xxx1615312????xx61(5x+1)=81(9x+1)-31(1-x)?????xxx3 4 112 5x x? ?? ?3 x? ?? ?2(x+1) 5(x+1)= 13 6-2 2 314 6y y? ?? ????xxxx53231223???????????????4 3 12 6 13 4 5x? ?? ?? ??? ?? ?? ?? ?4 5 x x? ???