2023衡水名师原创数学专题卷8.pdf

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­lj2(1-cos2a)-4Gsin2a+6(1+cos2a)=1,4\/3sin2a-4cos2a=7
Ai4sin2cr4¼cos2a=1,sin(2a-½)=Z,˜D
22868:.
7.A
i—|¾"=60","=¿,0=6| ÀfÁS=4-7y,ºÂÃyÃiS
sin3sine4k4
2
1
sinB=4*//?<cAB