晶面间距计算公式正交晶系1/d2=h2/a2+k2/b2+l2/c2单斜晶系1/d2={h2/a2+k2sin2β/b2+l2/c2-2hlcosβ/(ac)}/sin2β立方晶系d=a/(h2+k2+l2)六角晶系四角晶系单斜晶系三斜晶系IfΦistheanglebetweenplane(h1k1l1)and(h2k2l2),thenforOrthorhombicTetragonalCubicHexagonalVOLUME:Orthorhombic:=Tetragonal:=Cubic:=Hexagonal:=hcptransitionbetween(UVW)and(uvtw)U=u-t,V=v-t,W=wu=1/3(2U-V),v=1/3(2V-U),t=-(u+v),w=W.
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