湖北省仙桃市沔州中学2014年高考数学周卷(2)一、选择题(每小题5分,共50分)={(x,y)|y=x2,x∈R},B={(x,y)|y=x,x∈R},则集合A∩B中的元素个数为())34(log1)(22????xxxf的定义域为()A.[1,3]B.),3()1,(?????C.(1,3)D.)3,2()2,1(???的定义域为??3,2,1,0,那么其值域为()A.??3,0,1?B.??3,2,1,0C.??31???yyD.??30?? , 0,( )( 1), xf xf x x????? ??则4 4( ) ( )3 3f f? ?的值等于()A2?B4C2D4?{ | 0 6}, { | 0 3}A x x B y y? ?????,则下列对应关系中,不能看作从A到B的映射的是():2f x y x? ?B.:f x y x? ?:3f x y x? ?:6f x y x? ?()“若02x3x???,则1x?”的逆否命题为“若1x?,则02x3x???”B.“1x?”是“02x3x???”:p??,使得01xx???,则Rx:p???,均有01xx????为假命题,则p、( )f x的全体:对于任意0, 0,s t? ?都有( ) ( ) ( ).f s f t f s t? ??给出函数1 2 2( ) log , ( ) 2 1xf x x f x? ??.下列判断正确的是() 2( ) , ( )f x M f x M? ? 2( ) , ( )f x M f x?M? 2( ) , ( )f x M f x M? ? 2( ) , ( )f x M f x M? ?8.“| 1| 1x? ?”是“2log 1x?”的()=f(x)是定义在R上的奇函数,当x≥0时,f(x)=x2-2x,则在R上f(x)的解析式是()(x-2)B.|x|(x-2)(|x|-2)D.|x|(|x|-2),甲、乙两商场均采取了促销手段,其中甲为“全场八五折”,乙为“每满100元减20元”,则顾客购买100元以上商品到甲商场更合算的价位是()A??????200,3400B??????300,3800C??????200,3400???????300,3800D以上均不对二、填空题(每小题5分,共35分), 0( ) ,ln , 0xe x
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