挤压机挤压筒过盈计算.doc

挤压机挤压筒过盈计算
County continuation records has examined and approved the draft, spirit, believe, comprehensive Yeartered the phase of evaluation. Civil air defense work
County continuation records has examined and approved the draft, spirit, believe, comprehensive Yearbook of zhuanglang already prepared draft, entered the phase of evaluation. Civil air defense work
County continuation records has examined and approved the draft, spirit, believe, comprehensive Yearbook of zhuanglang already prepared draft, entered the phase of evaluation. Civil air defense work5 / 68
County continuation records has examined and approved the draft, spirit, believe, comprehensive Yearbook of zhuanglang already prepared draft, entered the phase of evaluation. Civil air defense work

挤压筒在挤压过程中受三向应力，分别为径向压力，周向压力和轴向压力，挤压沿轴向应力分布比较均匀，所以将挤压筒可简化为厚壁圆筒模型，即为平面应变问题，根据弹性力学计算三层圆挤压筒的接触应力及受内压时的应力应变。


等厚较长的圆筒，内外表面受有径向均匀分布的压力作用，并假定压力沿筒轴方向均相同。由于压力和物体本身的对称性，故变形后的圆筒对其轴线一定也是对称的，所以当利用极坐标时既没有切向位移也没有剪应力，这是轴对称的弹性力学平面应变问题。

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圆筒开口时不受轴向力，此时，
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整理计算得到
County continuation records has examined and approved the draft, spirit, believe, comprehensive Yearbook of zhuanglang already prepared draft, entered the phase of evaluation. Civil air defense work
County continuation records has examined and approved the draft, spirit, believe, comprehensive Yearbook of zhuanglang already prepared draft, entered the phase of evaluation. Civil air defense work6 / 68
County continuation records has examined and approved the draft, spirit, believe, comprehensive Yearbook of zhuanglang already prepared draft, entered the phase of evaluation. Civil air defense work
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经计算得到最终解为：
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其中积分常数、可由边界条件决定。

（一）圆筒受有均匀内压