????????????????????????????????????????????????????26SSSGED222;sin2cos3Gsin2cos3Esin2cos3D26SSSGED25425PQOM02sin42sin25PQOM2sin252sin52sin5PQOM42sin52sin122sin13cos2sin2sin3-cos3OM42sin52sin122sin13cos2sin2sin3cos3yyxxPQconsin222cos2sin2ysin-cos232sin3-cos3xyxMPQ2cossin2cos2sin23sincos3sin3-cos3xx)cos2sin3Q(-)2sin22cos3Q(Q222tt01sin26sin26sincossincos26sin2cos3sin2cos321yxyx21S2tt0)sin2cos3Q()sin2cos3P()y,Q(x)y,P(x20sin2cos3123xOEGODGODEOEGODGODE121212112111211211111211211221221211110111100012122121222112122121222111111212211212122112211221OPQ2**********???????????????????????????????????????????????????????????????????????????????????????????????????????????????????三点,满足、、因此,不存在点这三个等式矛盾;;,,根据上面结论,有,、,、,不妨设;三点,满足、、若存在点的最大值是时,显然,;所以, --+-又因为:,,则,中点设所以,,,即,坐标变为:;,得只取:,根据三角函数周期性由假设,)(解得:)( = )(设,,,的坐标变为:、,点的参数方程为解: 22EGDGDEGGEEDDtttttttttttttttttttttttttttttttttttttttttttyyttttttttttttttttttttttttttttttytxy??????????
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